JEE Main202227 Jul 2022Evening ShiftMathematicsSequences and SeriesActual
2 3 - 1 3 1 × 7 + 4 3 - 3 3 + 2 3 - 1 3 2 × 11 + 6 3 - 5 3 + 4 3 - 3 3 + 2 3 - 1 3 3 × 15 + … . . + 30 3 - 29 3 + 28 3 - 27 3 + … + 2 3 - 1 3 15 × 63 is equal to ______.
Correct answer
0
Step-by-step solution
Given series, 2 3 - 1 3 1 × 7 + 4 3 - 3 3 + 2 3 - 1 3 2 × 11 + 6 3 - 5 3 + 4 3 - 3 3 + 2 3 - 1 3 3 × 15 + … . . + 30 3 - 29 3 + 28 3 - 27 3 + … + 2 3 - 1 3 15 × 63 Now finding T n = ∑ k = 1 n 2 k 3 - 2 k - 1 3 n 4 n + 3 = ∑ k = 1 n 4 k 2 + 2 k - 1 2 + 2 k 2 k - 1 n 4 n + 3 = ∑ k = 1 n 12 k 2 - 6 k + 1 n 4 n + 3 = 2 n 2 n 2 + 3 n + 1 - 3 n 2 - 3 n + n n 4 n + 3 = n 2 4 n + 3 n 4 n + 3 = n So, T n = n Now finding S n = ∑ n = 1 15 T n = 15 × 16 2 = 120