JEE Main2015MathematicsSequences and SeriesActual
The value of ∑ r = 16 30 r + 2 ( r - 3 ) is equal to:
Options
- A7775
- B7785
- C7780
- D7770
Correct answer
C. 7780
Step-by-step solution
Given value = ∑ r = 16 30 r + 2 ( r - 3 ) = ∑ r = 1 30 r + 2 ( r - 3 ) - ∑ r = 1 15 r + 2 ( r - 3 ) = n n + 1 2 n + 1 6 - n n + 1 2 - 6 n - m m + 1 2 m + 1 6 - m m + 1 2 - 6 m where n = 30 ,   m = 15 = 8810 - 1030 = 7780