Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main2014MathematicsSequences and SeriesActual

Let G be the geometric mean of two positive numbers a and b , and M be the arithmetic mean of 1 a and 1 ~b . If 1 M : G is 4: 5 , then a : b can be:

Options

  1. A1: 4
  2. B1: 2
  3. C2: 3
  4. D3: 4

Correct answer

A. 1: 4

Step-by-step solution

G = a b aligned & M = 1 a + 1 b 2 & M = a+b 2 a b aligned Given that 1 M : G =4: 5 aligned & 2 a b (a+b) a b = 4 5 & a+b 2 a b = 5 4 & a+b+2 a b a+b-2 a b = 5+4 5-4 aligned Using Componendo & Dividendo aligned & ( a )^2+( b )^2+2 a b ( a )^2+( b )^2-2 a b = 9 1 & ( b + a )^2 b - a )^2= 9 1 b + a b - a = 3 1 & b + a + b - a b + a - b + a = 3+1 3-1 aligned Using Componendo & Dividendo b a = 4 2 =2 aligned b a &= 4 1 a b &= 1 4 a: b=1: 4 aligned

Practice Sequences and Series on Quantrex Academy →

More from Sequences and Series

Let = 3+4+8+9+13+14+ upto 40 terms. If ( )^ 1020 is a root of the equation x^2+x-2=0 , (0, 2 ) , then ^2 + 3 ^2 is equal to: 2026The sum 1 + 1 2 (1^2 + 2^2) + 1 3 (1^2 + 2^2 + 3^2) + upto 10 terms is equal to : 2026The value of 1^3 - 2^3 + 3^3 - + 15^3 is: 2026The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8 . If the first term of the A.P. is equal to the common ratio of the G.P. and the 2026For the functions f( ) = ^2 + ^2 , and g( ) = ^2 + ^2 , > > 0 , let _ 0 < < /2 f( ) = _ 0 < < g( ) . If the first term of a G.P. is ( 2 ) , its common ratio is ( 2 ) and the sum of 2026If the sum of the first 10 terms of the series 1 1 + 1^4 4 + 2 1 + 2^4 4 + 3 1 + 3^4 4 + 4 1 + 4^4 4 + is m n , (m, n) = 1 , then m + n is equal to : 2026Let A₁, A₂, A₃, , A₃₉ be 39 arithmetic means between the numbers 59 and 159 . Then the mean of A₂₅, A₂₈, A₃₁ and A₃₆ is equal to : 2026Let the sum of the first n terms of an A.P. be 3n^2 + 5n . Then the sum of squares of the first 10 terms of the A.P. is: 2026 Full Sequences and Series list All JEE Main PYQs