JEE Main2013MathematicsSequences and SeriesActual
The sum of the series : (2)^2+2(4)^2+3(6)^2+ upto 10 terms is :
Options
- A11300
- B11200
- C12100
- D12300
Correct answer
C. 12100
Step-by-step solution
2^2+2(4)^2+3(6)^2+ upto 10 terms =2^2 [1^3+2^3+3^3+ . upto 10 terms ]=4 ( 10 11 2 )^2=12100