JEE Main2012MathematicsSequences and SeriesActual
The sum of the series 1^2+2.2^2+3^2+2.4^2+5^2+2.6^2+ . .+2(2 m)^2 is
Options
- Am(2 m+1)^2
- Bm^2(m+2)
- Cm^2(2 m+1)
- Dm(m+2)^2
Correct answer
A. m(2 m+1)^2
Step-by-step solution
The sum of the given series 1^2+2.2^2+3^2+2.4^2+5^2+2.6^2+ . .+2(2 m)^2 is 2 m (2 m+1^2 . 2 m (2 m+1^2 )