JEE Main2004MathematicsSequences and SeriesActual
If u= a^2 ^2 +b^2 ^2 + a^2 ^2 +b^2 ^2 , then the difference between the maximum and minimum values of u^2 is given by
Options
- A2 (a^2+b^2 )
- B2 a^2+b^2
- C(a+b)^2
- D(a-b)^2
Correct answer
D. (a-b)^2
Step-by-step solution
u= a^2 ^2 +b^2 ^2 + a^2 ^2 +b^2 ^2 = a^2+b^2 2 + a^2-b^2 2 2 + a^2+b^2 2 + b^2-a^2 2 2 u^2=a^2+b^2+2 ( a^2+b^2 2 )^2- ( a^2-b^2 2 )^2 ^2 2 min value of u^2=a^2+b^2+2 a b max value of u^2=2 (a^2+b^2 ) u_ ^2-u_ ^2=(a-b)^2 .