JEE Main202621 January 2026Evening ShiftMathematicsSets and RelationsActual

Let A = x: |x²-10 | 6 and B = x:|x-2|>1 . Then

Options

AA B =(- , 1] (2, )
BB - A =(- ,-4) (-2,1) (4, )
CA - B =[2,3)
DA ~B =[-4,-2] [3,4]

Correct answer

B. B - A =(- ,-4) (-2,1) (4, )

Step-by-step solution

A = x : |x^2 - 10| 6 : -6 x^2 - 10 6 4 x^2 16 , so A = [-4, -2] [2, 4] . B = x : |x - 2| > 1 = (- , 1) (3, ) . A^c = (- , -4) (-2, 2) (4, ) . B - A = B A^c = [(- , 1) A^c] [(3, ) A^c] = [(- , -4) (-2, 1)] [(4, )] = (- , -4) (-2, 1) (4, ) .

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