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JEE Main 202118 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Evening Shift
Subject
Mathematics
Chapter
Sets and Relations

JEE Main 2021 · 18 March · Evening Shift · Mathematics · Sets and Relations

Define a relation R over a class of n × n real matrices A and B as...

Define a relation RR over a class of n×nn \times n real matrices AA and BB as "ARBARB iff there exists a non-singular matrix PP such that PAP−1=BPA{P}^{- 1} = B". Then which of the following is true ?

Options

  1. ARR is symmetric, transitive but not reflexive
  2. BRR is reflexive, symmetric but not transitive
  3. CRR is an equivalence relation
  4. DRR is reflexive, transitive but not symmetric

Correct answer

C. RR is an equivalence relation

Step-by-step solution

Given AA and BB are matrices of n×nn \times n order and ARBARB iff there exists a non-singular matrix PP\left(det \left(P\right) \ne 0\right) such that PAP−1=BPA{P}^{- 1} = B.

Reflexivity Check :

ARA⇒PAP−1=AARA ⇒ PA{P}^{- 1} = A which is true for P=IP = I.

So, RR is reflexive relation.

Symmetric Check :

ARB⇒PAP−1=B⇒P−1PAP−1P=P−1BP⇒IAI=P−1BP⇒P−1BP=A⇒BRAARB ⇒ PA{P}^{- 1} = B ⇒ {P}^{- 1}PA{P}^{- 1}P = {P}^{- 1}BP ⇒ IAI = {P}^{- 1}BP ⇒ {P}^{- 1}BP = A ⇒ BRA for matrix P−1{P}^{- 1}.

So, RR is symmetric relation.

Transitivity Check :

ARB⇒PAP−1=BARB ⇒ PA{P}^{- 1} = B and BRC⇒PBP−1=CBRC ⇒ PB{P}^{- 1} = C.

So, PPAP−1P−1=CPPA{P}^{- 1}{P}^{- 1} = C.

⇒P2A(P2)−1=C⇒ARC⇒ {P}^{2}A{\left({P}^{2}\right)}^{- 1} = C ⇒ ARC

So, RR is a transitive relation.

Since, RR is reflexive, symmetric and transitive all.

Hence, RR is an equivalence relation.

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