Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main20206 Sep 2020Morning ShiftMathematicsStatisticsActual

If Σ i = 1 n x i - a = n and Σ i = 1 n x i - a 2 = n a , n , a > 1 , then the standard deviation of n observations x 1 , x 2 , … , x n is

Options

  1. Aa - 1
  2. Bn ( a - 1 )
  3. Cn ( a - 1 )
  4. D( a - 1 )

Correct answer

D. ( a - 1 )

Step-by-step solution

SD, σ = ∑ x i 2 n - ∑ x i n 2 SD is independent of change of origin, so, for given data σ = Σ x i - a 2 n - Σ x i - a n 2 = n a n - n n 2 = a - 1

Practice Statistics on Quantrex Academy →

More from Statistics

Consider a data consisting of 10 observations x₁, x₂, , x₁₀ , whose mean is 5 and variance is 7 . If the mean and the variance of the first 8 observations x₁, x₂, , x₈ are 4 and 3. 2026A set of four observations has mean 1 and variance 13 . Another set of six observations has mean 2 and variance 1 . Then, the variance of all these 10 observations is equal to: 2026Let the mean and the variance of seven observations 2, 4, , 8, , 12, 14 , < , be 8 and 16 respectively. Then the quadratic equation whose roots are 3 + 2 and 2 + 1 is : 2026A data consists of 20 observations x₁, x₂, , x₂₀ . If _ i=1 ²⁰(x_i + 5)^2 = 2500 and _ i=1 ²⁰(x_i - 5)^2 = 100 , then the ratio of mean to standard deviation of this data is: 2026A variable X takes values 0, 0, 2, 6, 12, 20, , n(n-1) with frequencies ^nC₀, ^nC₁, ^nC₂, ^nC₃, ^nC₄, ^nC₅, , ^nC_n , respectively. If the mean of this data is 60 , then its median 2026The mean deviation about the mean for the data x_i 5 7 9 10 12 15 f_i 8 6 2 2 2 6 is equal to: 2026For 10 observations x₁, x₂, , x₁₀ , if _ i=1 ¹⁰(x_i+2)^2=180 and _ i=1 ¹⁰(x_i-1)^2=90 , then their standard deviation is: 2026Suppose that the mean and median of the non-negative numbers 21, 8, 17, a, 51, 103, b, 13, 67, (a > b) , are 40 and 21 , respectively. If the mean deviation about the median is 26 2026 Full Statistics list All JEE Main PYQs