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JEE Main 20205 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
5 September
Shift
Evening Shift
Subject
Mathematics
Chapter
Statistics

JEE Main 2020 · 5 September · Evening Shift · Mathematics · Statistics

If the mean and the standard deviation of the data 3, 5, 7, a, b...

If the mean and the standard deviation of the data 3,5,7,a,b3, 5, 7, a, b are 55and 22 respectively, then aa and bb are the roots of the equation:

Options

  1. Ax2−10x+18=0{x}^{2} - 10x + 18 = 0
  2. B2x2−20x+19=02{x}^{2} - 20x + 19 = 0
  3. Cx2−10x+19=0{x}^{2} - 10x + 19 = 0
  4. Dx2−20x+18=0{x}^{2} - 20x + 18 = 0

Correct answer

C. x2−10x+19=0{x}^{2} - 10x + 19 = 0

Step-by-step solution

5+3+7+a+b=25⇒a+b=105 + 3 + 7 + a + b = 25 ⇒ a + b = 10
S.D. =52+32+72+a2+b25−52=2= \sqrt{\dfrac{{5}^{2} + {3}^{2} + {7}^{2} + {a}^{2} + {b}^{2}}{5} - {5}^{2}} = 2
=a2+b2+835−25=4⇒a2+b2=62= \dfrac{{a}^{2} + {b}^{2} + 83}{5} - 25 = 4 ⇒ {a}^{2} + {b}^{2} = 62
⇒(a+b)2−2ab=62⇒ab=19⇒ ( a + b{)}^{2} - 2ab = 62 ⇒ ab = 19
so equation whose roots are a and b is x2−10x+19=0{x}^{2} - 10x + 19 = 0
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