AP EAMCET202422 May 2024Evening ShiftChemistryGeneral Organic ChemistryActual
Species A, B, C, D formed in the following bond cleavages respectively are
Options
- ACH ₃ CH ₂⁺, I ⁻, CH ₃ CH ₂⁻, Cu ⁺
- BCH ₃ CH ₂⁺, I ⁻, CH ₃ CH ₂⁺, Cu ⁻
- CCH ₃ CH ₂⁻, I ⁺, CH ₃ CH ₂⁺, Cu ⁻
- DCH ₃ CH ₂⁻, I ⁺, CH ₃ CH ₂⁻, Cu ⁺
Correct answer
A. CH ₃ CH ₂⁺, I ⁻, CH ₃ CH ₂⁻, Cu ⁺
Step-by-step solution
Iodine is good living group so it generate the carbocation. Here; Cu is giving electron to the carbon atom so it act as a reducing agent. So a carbanion is form.