Using Duma's method for estimating nitrogen l g of an organic compound X gave 82 ~mL of nitrogen, collected at 27^ C and 750 ~mm Hg pressure. If the aqueous tension at 27^ C is 30 ~mm Hg pressure, then the percentage of nitrogen in the given compound X is

Step-by-step solution

For 750 mm pressure, subtract aqueous tension 30 mm to obtain pressure of nitrogen. p = 750 − 30 = 720mm of Hg Now, volume of nitrogen at STP = V p 273 T 760 aligned & = 82 720 273 300 760 & = 1.6117 10^7 228000 = 1.6117 10^4 228 & =70.68 ~mL aligned Percentage of nitrogen aligned & = vol. of N ₂ at STP wt. of organic compound 28 22400 100 & = 70.68 1 28 22400 100=88.36 % aligned The percentage composition of nitrogen in the compound would be 88.36 % .