An organic compound of molecular formula C 6 H 6 Br 2 has six carbon atoms in a ring system, two non-conjugate double bonds and two bromo groups at 1 , 4 positions. Then the compound is

Step-by-step solution

C 6 H 6 Br 2 :- Double bond equivalent formula = C - H 2 - X 2 + 1 C = 6 ;   H = 6 ; X = 2 DBU = 6 - 6 2 - 2 2 + 1 = 6 - 4 + 1 = 3 So, it has one ring with two double bonds. It has the two bromo groups at the 1 , 4 position and has the six membered carbon ring with non-conjugated double bond. Hence, the structure of compound is :- . Hence, the above compound is homo-cyclic but not aromatic.