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JEE Main 202329 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
29 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Vector Algebra

JEE Main 2023 · 29 January · Morning Shift · Mathematics · Vector Algebra

If the vectors → a = λ ^ i + μ ^ j + 4 ^ k , → b = - 2 ^ i + 4 ^ j...

If the vectors \overset{\to}{a} = \lambda\overset{^}{i} + \mu\overset{^}{j} + 4\overset{^}{k}, \overset{\to}{b} = - 2\overset{^}{i} + 4\overset{^}{j} - 2\overset{^}{k} and \overset{\to}{c} = 2\overset{^}{i} + 3\overset{^}{j} + \overset{^}{k} are coplanar and the projection of a→\overset{\to}{a} on the vector b→\overset{\to}{b} is 54\sqrt{54} units, then the sum of all possible values of λ+μ\lambda + \mu is equal to

Options

  1. A00
  2. B66
  3. C2424
  4. D1818

Correct answer

C. 2424

Step-by-step solution

Given,

\overset{\to}{a} = \lambda\overset{^}{i} + \mu\overset{^}{j} + 4\overset{^}{k}, \overset{\to}{b} = - 2\overset{^}{i} + 4\overset{^}{j} - 2\overset{^}{k} and \overset{\to}{c} = 2\overset{^}{i} + 3\overset{^}{j} + \overset{^}{k} are coplanar

So, \left|{λμ4−24−2231\begin{cases}\lambda & \mu & 4 \\ - 2 & 4 & - 2 \\ 2 & 3 & 1\end{cases}\right| = 0</p><p></p><p>⇒ \lambda ( 10 ) - \mu ( 2 ) + 4 ( - 14 ) = 0</p><p></p><p>⇒ 10\lambda - 2\mu = 56</p><p></p><p>⇒ 5\lambda - \mu = 28 . . . . . \left(1\right)</p><p>Andgivenprojectionof</p><p>And given projection of\overset{\to}{a}onon\overset{\to}{b}isis\sqrt{54}</p><p></p><p>⇒ \dfrac{\overset{\to}{a} \cdot \overset{\to}{b}}{| \overset{\to}{b} |} = \sqrt{54}</p><p></p><p>⇒ \dfrac{- 2\lambda + 4\mu - 8}{\sqrt{24}} = \sqrt{54}</p><p></p><p>⇒ - 2\lambda + 4\mu - 8 = \sqrt{54 \times 24} . . . . \left(2\right)</p><p>Bysolvingequation(1) and (2)</p><p>By solving equation \left(1\right) \text{ and } \left(2\right) we get,

⇒λ+μ=24⇒ \lambda + \mu = 24

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