JEE Main 202329 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 29 January
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Vector Algebra
JEE Main 2023 · 29 January · Morning Shift · Mathematics · Vector Algebra
If the vectors → a = λ ^ i + μ ^ j + 4 ^ k , → b = - 2 ^ i + 4 ^ j...
If the vectors \overset{\to}{a} = \lambda\overset{^}{i} + \mu\overset{^}{j} + 4\overset{^}{k}, \overset{\to}{b} = - 2\overset{^}{i} + 4\overset{^}{j} - 2\overset{^}{k} and \overset{\to}{c} = 2\overset{^}{i} + 3\overset{^}{j} + \overset{^}{k} are coplanar and the projection of on the vector is units, then the sum of all possible values of is equal to
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
Given,
\overset{\to}{a} = \lambda\overset{^}{i} + \mu\overset{^}{j} + 4\overset{^}{k}, \overset{\to}{b} = - 2\overset{^}{i} + 4\overset{^}{j} - 2\overset{^}{k} and \overset{\to}{c} = 2\overset{^}{i} + 3\overset{^}{j} + \overset{^}{k} are coplanar
So, \left|\right| = 0⇒ \lambda ( 10 ) - \mu ( 2 ) + 4 ( - 14 ) = 0⇒ 10\lambda - 2\mu = 56⇒ 5\lambda - \mu = 28 . . . . . \left(1\right)\overset{\to}{a}\overset{\to}{b}\sqrt{54}⇒ \dfrac{\overset{\to}{a} \cdot \overset{\to}{b}}{| \overset{\to}{b} |} = \sqrt{54}⇒ \dfrac{- 2\lambda + 4\mu - 8}{\sqrt{24}} = \sqrt{54}⇒ - 2\lambda + 4\mu - 8 = \sqrt{54 \times 24} . . . . \left(2\right) we get,