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JEE Main 202522 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Evening Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2025 · 22 January · Evening Shift · Physics · Alternating Current

A series LCR circuit is connected to an alternating source of emf...

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is I0I_0. If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be

Options

  1. A22\mathrm{I}0_0
  2. BI0I_0
  3. C\frac{\mathrm{I}_0}{2}
  4. D\frac{\mathrm{I}_0}{\sqrt{2}}

Correct answer

C. \frac{\mathrm{I}_0}{2}

Step-by-step solution

Initially, I0=εmR\mathrm{I}_0=\frac{\varepsilon_{\mathrm{m}}}{\mathrm{R}} Finally, \mathrm{I}_0^1=\frac{\varepsilon_{\mathrm{m}}}{2 \mathrm{R}}=\frac{\mathrm{I}_0}{2}
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