JEE Main202429 Jan 2024Evening ShiftPhysicsAlternating CurrentActual

In the given figure, the charge stored in 6 μ F capacitor, when points A and B are joined by a connecting wire is _______ μ C .

Correct answer

Step-by-step solution

At steady state, capacitor behaves as an open circuit and current flows in circuit as shown in the diagram. R eq = 9 Ω i = 9 V 9 Ω = 1 A Δ V 6 Ω = 1 × 6 = 6 V V A = 3 V So, potential difference across 6 μ F is 6 V . Hence, Q = C Δ V = 6 × 6 × 10 - 6 C = 36 μ C

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