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JEE Main202331 Jan 2023Evening ShiftPhysicsAlternating CurrentActual

An alternating voltage source V = 260 sin ( 628 t ) is connected across a pure inductor of 5 mH . Inductive reactance in the circuit is:

Options

  1. A3 . 14 Ω
  2. B6 . 28 Ω
  3. C0 . 5 Ω
  4. D0 . 318 Ω

Correct answer

A. 3 . 14 Ω

Step-by-step solution

Comparing the given equation of AC voltage with standard expression, V = V 0 sin ω t , we get ω = 628   rad   s - 1 . Inductive reactance is given by, X L = ω L . = 628 × 5 × 10 - 3 = 3 . 14   Ω

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