A series LCR circuit consists of R = 80 Ω . X _ L = 100 Ω , and X _...

Comparing input voltage with standard expression, $V = {V}_{0}\cos \left(\omegat\right)$, we get $\omega = 100\pi$.

Now, impedance $Z = \sqrt{{R}^{2} + {\left({X}_{L} - {X}_{C}\right)}^{2}}$

$= \sqrt{{80}^{2} + {\left(100 - 40\right)}^{2}}$

$= 100Ω$

Therefore, peak current

${i}_{0} = \dfrac{{V}_{0}}{Z} = \dfrac{2500}{100}A = 25A$