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JEE Main 202330 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Evening Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2023 · 30 January · Evening Shift · Physics · Alternating Current

In the given circuit, rms value of current ( I _ rms ) through the...

In the given circuit, rmsrms value of current (Irms)\left({I}_{rms}\right) through the resistor RR is :

In the given circuit, rms value of current ( I _ rms ) through the resistor R is :

Options

  1. A2A2A
  2. B12A\dfrac{1}{2}A
  3. C20A20A
  4. D22A2\sqrt{2}A

Correct answer

A. 2A2A

Step-by-step solution

In the given circuit, rms value of current ( I _ rms ) through the resistor R is :

Impedance of the given LCR circuit will be, Z=R2+(XL−XC)2⇒Z=1002+(200−100)2Z = \sqrt{{R}^{2} + {\left({X}_{L} - {X}_{C}\right)}^{2}} ⇒ Z = \sqrt{{100}^{2} + {\left(200 - 100\right)}^{2}}

=1002Ω= 100\sqrt{2}Ω

Therefore, RMS current can be written as,

Irms=VrmsZ=20021002{I}_{rms} = \dfrac{{V}_{rms}}{Z} = \dfrac{200\sqrt{2}}{100\sqrt{2}}

=2A= 2A

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