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JEE Main202331 Jan 2023Morning ShiftPhysicsAlternating CurrentActual

An inductor of 0 . 5 mH , a capacitor of 20 μF and resistance of 20 Ω are connected in series with a 220 V ac source. If the current is in phase with the emf, the amplitude of current of the circuit is x A . The value of x is-

Correct answer

0

Step-by-step solution

Here, emf and current are in phase, so the circuit is either pure resistive circuit or case of resonance, X L = X C Thus, the impedance of circuit is Z = R 2 + X L - X C 2 = R = 20   Ω Now, rms value of current is i rms = 220 20 = 11   A Using the relation between peak and rms value of current, we have peak value i 0 = i rms 2 = 11 2 = 242   A . Hence, the value of x = 242 .

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