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JEE Main 202325 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
25 January
Shift
Evening Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2023 · 25 January · Evening Shift · Physics · Alternating Current

A series LCR circuit is connected to an AC source of 220V , 50Hz ....

A series LCR circuit is connected to an AC source of 220V220V, 50Hz50Hz. The circuit contains a resistance R=80ΩR = 80Ω, an inductor of inductive reactance XL=70Ω{X}_{L} = 70Ω, and a capacitor of capacitive reactance XC=130Ω{X}_{C} = 130Ω. The power factor of circuit is x10\dfrac{x}{10}. The value of xx is:

Correct answer

0

Step-by-step solution

Power factor in LCR circuit is given by,

cosϕ=RZcosϕ = \dfrac{R}{Z}, where, ZZ is the total impedance of the circuit.

So, cosϕ=RR2+(XC−XL)2cosϕ = \dfrac{R}{\sqrt{{R}^{2} + {\left({X}_{C} - {X}_{L}\right)}^{2}}}

Putting the values, we have

⇒cosϕ=80(80)2+(60)2⇒ cosϕ = \dfrac{80}{\sqrt{( 80{)}^{2} + ( 60{)}^{2}}}

⇒cosϕ=80100⇒810⇒ cosϕ = \dfrac{80}{100} ⇒ \dfrac{8}{10}

Thus, the value of x=8x = 8.

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