In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes x times its initial resonant frequency ω 0 . The value of x is:

Question

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes x times its initial resonant frequency &#969; 0 . The value of x is:

Quantrex Academy · Accepted Answer

Correct answer: A. 1 4

Resonance frequency of an LC oscillations circuit is stated as &#969; 0 = 1 L C , here, L &#160; and &#160; C represents inductance and capacitance of circuit. Now, when inductance and capacitance changes, i.e., L ' = 2 L and C ' = 8 C Then, resonant frequency is &#969; = 1 2 L &#215; 8 C = 1 4 L C &#8658; &#969; = &#969; 0 4 Thus, the value of x = 1 4 .

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes x times its initial resonant frequency ω 0 . The value of x is:

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Correct answer

Step-by-step solution

More from Alternating Current

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes x times its initial resonant frequency &#969; 0 . The value of x is:

Options

Correct answer

Step-by-step solution

More from Alternating Current

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes x times its initial resonant frequency ω 0 . The value of x is: