An LCR series circuit of capacitance 62 . 5 nF and resistance of 50 Ω , is connected to an A.C. source of frequency 2 . 0 kHz . For maximum value of amplitude of current in circuit, the value of inductance is ____ mH . ( Take π 2 = 10

Step-by-step solution

Given here, f = 2   kHz = 2000   Hz ,   C = 62 . 5   nF = 62 . 5 × 10 - 9   F   and   R = 50   Ω Resonance frequency (amplitude of the current will be maximum in this case) is given by f = 1 2 π L C , here, L is the inductance. Putting the values, 2000   Hz = 1 2 π L × 62 . 5 × 10 - 9 L = 1 4 π 2 × 2000 2 × 62 . 5 × 10 - 9 = 0 . 1   H = 100   mH