A sinusoidal voltage V(t) = 210 3000t volt is applied to a series...

Capacitive reactance is ${X}_{C} = \dfrac{1}{\omegaC} = \dfrac{1}{3000 \times 25 \times {10}^{- 6}} = \dfrac{40}{3}Ω$

Inductive reactance is ${X}_{L} = \omegaL = 3000 \times 10 \times {10}^{- 3} = 30Ω$

Now, total reactance is $X = {X}_{L} - {X}_{C}$

$= 30 - \dfrac{40}{3} = \dfrac{50}{3}Ω$

$tanϕ = \dfrac{X}{R} = \dfrac{\dfrac{50}{3}}{100} = \dfrac{1}{6}$

$tanϕ = \dfrac{1}{6} = 0 . 17$

Hence, the phase difference between the applied voltage and resultant current is $\tan^{- 1}\left(0 . 17\right)$.