In a series LCR circuit, the inductance, capacitance and resistance...

Angular frequency, $\omega = 2\pif = 100\pi rad{s}^{- 1}$

Here, inductive reactance ${X}_{L} = \omegaL = \left(100\pi\right)\left(100 \times {10}^{- 3}\right) = 10\piΩ$

And capacitive reactance${X}_{C} = \dfrac{1}{\omegaC} = \dfrac{1}{\left(100\pi\right) \times \left(100 \times {10}^{- 6}\right)} = \dfrac{100}{\pi}Ω = 10\piΩ$

Now, impedance of the series circuit is $Z = \sqrt{{R}^{2} + {\left({X}_{L} - {X}_{C}\right)}^{2}} = R = 10Ω$

Therefore,

${I}_{RMS} = \dfrac{{V}_{RMS}}{Z}$,

$= \dfrac{220}{10} = 22A$