Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202131 AugustMorning Shift
Exam
JEE Main
Year
2021
Date
31 August
Shift
Morning Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2021 · 31 August · Morning Shift · Physics · Alternating Current

In an ac circuit, an inductor, a capacitor and a resistor are...

In an ac circuit, an inductor, a capacitor and a resistor are connected in series with XL=R=XC.{X}_{L} = R = {X}_{C} . Impedance of this circuit is :

Options

  1. AZero
  2. BRR
  3. CR2R\sqrt{2}
  4. D2R22{R}^{2}

Correct answer

B. RR

Step-by-step solution

Recall the formula of impedance is in terms of resistance, Z=(XL−XC)2+R2Z = \sqrt{{\left({X}_{L} - {X}_{C}\right)}^{2} + {R}^{2}}, here, the condition of resonance, XL=XC{X}_{L} = {X}_{C}, it means,
Z=(XL−XL)2+R2=RZ = \sqrt{{\left({X}_{L} - {X}_{L}\right)}^{2} + {R}^{2}} = R
Practice Alternating Current on Quantrex Academy →

More from Alternating Current

Consider a circuit consisting of a capacitor of capacitance C and a coil with N turns per… JEE Advanced 2026A LCR series circuit driven with E_ rms = 90 V at frequency f_d = 30 Hz has resistance R… JEE Main 2026A series LCR circuit with R = 20\ Ω , L = 1.6 H and C = 40\ is connected to a variable… JEE Main 2026An a.c. source of angular frequency ω is connected across a resistor R and a capacitor C… JEE Main 2026An inductor of 10 mH, capacitor of 0.1\ μ F and a resistor of 100\ Ω are connected in… JEE Main 2026The figure given below shows an LCR series circuit with two switches S_1 and S_2 . When… JEE Main 2026An inductor stores 16 J of magnetic field energy and dissipates 32 W of thermal energy… JEE Main 2026The electric current in the circuit is given as i=i_ o (t / T) . The r.m.s current for… JEE Main 2026 Full Alternating Current list All JEE Main PYQs