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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2021 · 27 August · Evening Shift · Physics · Alternating Current

An AC circuit has an inductor and a resistor of resistance R in...

An AC circuit has an inductor and a resistor of resistance RR in series, such that XL=3R{X}_{L} = 3R. Now, a capacitor is added in series such that XC=2R{X}_{C} = 2R. the ratio of the new power factor with the old power factor of the circuit is 5:x\sqrt{5}: x. The value of xx is

Correct answer

0

Step-by-step solution

First Recall the formula of power factor, cosϕ=RZcosϕ = \dfrac{R}{Z}⇒cosϕinitial=RZ=R(XL)2+R2=R9R2+R2=110⇒ cos{ϕ}_{initial} = \dfrac{R}{Z} = \dfrac{R}{\sqrt{{\left({X}_{L}\right)}^{2} + {R}^{2}}} = \dfrac{R}{\sqrt{9{R}^{2} + {R}^{2}}} = \dfrac{1}{\sqrt{10}}.

⇒cosϕfinal=RZ=R(XL−XC)2+R2=RR2+R2=12⇒ cos{ϕ}_{final} = \dfrac{R}{Z} = \dfrac{R}{\sqrt{{\left({X}_{L} - {X}_{C}\right)}^{2} + {R}^{2}}} = \dfrac{R}{\sqrt{{R}^{2} + {R}^{2}}} = \dfrac{1}{\sqrt{2}}

⇒cosϕfinalcosϕinitial=5x⇒x=1⇒ \dfrac{cos{ϕ}_{final}}{cos{ϕ}_{initial}} = \dfrac{\sqrt{5}}{x} ⇒ x = 1

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