JEE Main202126 Aug 2021Morning ShiftPhysicsAlternating CurrentActual
A series LCR circuit driven by 300 V at a frequency of 50 Hz contains a resistance R = 3 kΩ , an inductor of inductive reactance X L = 250 π Ω and an unknown capacitor. The value of capacitance to maximise the average power should be: take π 2 = 10
Options
- A400   μF
- B4   μ F
- C40   μ F
- D25   μ F
Correct answer
B. 4   μ F
Step-by-step solution
Angular frequency, ω = 2 π f = 2 π × 50 = 100 π   rad   s - 1 At resonance, X C = X L ⇒ 1 ωC = ωL ⇒ 1 ωC = 250 π ⇒ C = 1 100 π × 250 π   F = 4   μF