Two circuits are shown in figure ( a ) and ( b ) . At a frequency of _______ rad s - 1 the average power dissipated in one cycle will be the same in both the circuits.

Step-by-step solution

For figure ( a ) P avg = V rms 2 R v rms 2 Z 2 × R = v rms 2 R × 1 R 2 = Z 2 25 = x C - x L 2 + 5 2 2 25 = x c - x L 2 + 25 x c = x L ⇒ 1 ω C = ω L ω 2 = 1 L C = 10 6 0 . 1 × 40 ω = 500