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JEE Main202120 Jul 2021Evening ShiftPhysicsAlternating CurrentActual

A series LCR circuit of R = 5 Ω , L = 20 mH and C = 0 . 5 μ F is connected across an AC supply of 250 V , having variable frequency. The power dissipated at resonance condition is ________ × 10 2 W .

Correct answer

0

Step-by-step solution

X L = X C (due to resonance) Z = R so i rms = V Z = V R V 2 R = 250 × 250 5 = 125 × 10 2   W

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