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JEE Main202120 Jul 2021Morning ShiftPhysicsAlternating CurrentActual

A C voltage V ( t ) = 20 sin ω t of frequency 50 Hz is applied to a parallel plate capacitor. The separation between the plates is 2 mm and the area is 1 m 2 . The amplitude of the oscillating displacement current for the applied A C voltage is Take ε 0 = 8 . 85 × 10 - 12 F m - 1

Options

  1. A21 . 14   μA
  2. B83 . 37   μA
  3. C27 . 79   μA
  4. D55 . 58   μA

Correct answer

C. 27 . 79   μA

Step-by-step solution

From the given information, C = ∈ 0   A   d = ϵ 0 × 1 2 × 10 - 3   F ∴   X C = 1 ω C = 2 × 10 - 3 2 × 50 π × ∈ 0 = 2 × 10 - 3 25 × 4 π ∈ 0   Ω ∴   X C = 2 × 10 - 3 25 × 9 × 10 9 = 18 25 × 10 6   Ω ∴   i 0 = V 0 X C = 20 × 25 18 × 10 - 6   A = 27 . 47   μA . The value of amplitude of displacement current will be same as value of amp

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