AC voltage V ( t ) = 20sin of frequency 50Hz is applied to a...

From the given information,

$C = \dfrac{{\in}_{0}A}{d} = \dfrac{{ϵ}_{0} \times 1}{2 \times {10}^{- 3}}F$
$∴ {X}_{C} = \dfrac{1}{\omegaC} = \dfrac{2 \times {10}^{- 3}}{2 \times 50\pi \times {\in}_{0}} = \dfrac{2 \times {10}^{- 3}}{25 \times 4\pi{\in}_{0}}Ω$
$∴ {X}_{C} = \dfrac{2 \times {10}^{- 3}}{25} \times 9 \times {10}^{9} = \dfrac{18}{25} \times {10}^{6}Ω$
$∴ {i}_{0} = \dfrac{{V}_{0}}{{X}_{C}} = \dfrac{20 \times 25}{18} \times {10}^{- 6}A = 27 . 47\text{\mu A} .$

The value of amplitude of displacement current will be same as value of amplitude of conventional current.
Hence option $3 .$