JEE Main202116 Mar 2021Morning ShiftPhysicsAlternating CurrentActual
A sinusoidal voltage of peak value 250 V is applied to a series L C R circuit, in which R = 8 Ω , L = 24 mH and C = 60 μ F . The value of power dissipated at resonant condition is x kW . The value of x to the nearest integer is _______.
Correct answer
0
Step-by-step solution
At resonance power, P = V rms 2 R P = 250 / 2 2 8 = 3906 . 25   W ≈ 4   kW