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JEE Main 202116 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Morning Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2021 · 16 March · Morning Shift · Physics · Alternating Current

A sinusoidal voltage of peak value 250V is applied to a series LCR...

A sinusoidal voltage of peak value 250V250V is applied to a series LCRLCR circuit, in which R=8Ω,L=24mHR = 8Ω, L = 24mH and C=60\muFC = 60\muF. The value of power dissipated at resonant condition is xx kWkW. The value of xx to the nearest integer is _______.

Correct answer

0

Step-by-step solution

At resonance power, P=(Vrms)2RP = \dfrac{{\left({V}_{rms}\right)}^{2}}{R}

P=(250/2)28=3906.25WP = \dfrac{{\left(250 / \sqrt{2}\right)}^{2}}{8} = 3906 . 25W

≈4kW\approx 4kW

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