JEE Main202126 Feb 2021Evening ShiftPhysicsAlternating CurrentActual
Find the peak current and resonant frequency of the following circuit (as shown in figure).
Options
- A2   A and 50   Hz
- B0 . 2   A and 100   Hz
- C2   A and 100   Hz
- D0 . 2   A and 50   Hz
Correct answer
D. 0 . 2   A and 50   Hz
Step-by-step solution
as given Z = X L - X C 2 + R 2 X L = ω L = 100 × 100 × 10 - 3 = 10   Ω X C = 1 ω C = 1 100 × 100 × 10 - 6 = 100   Ω Z = 10 - 100 2 + R 2 = 90 2 + 120 2 = 30 × 5 = 150   Ω i peak   = V peak z = 30 150 = 1 5   amp = 0 . 2   amp & For resonant frequency ⇒ ω L = 1 ω C ⇒ ω 2 = 1 L C ⇒ ω = 1 L C &   f = 1 2 π L C ⇒ 1 2 π 100 × 10 - 3 × 100 × 10 - 6 = 100 10 2 &#