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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2020 · 7 January · Morning Shift · Physics · Alternating Current

A LCR circuit behaves like a clamped harmonic oscillator. Comparing...

A LCRLCR circuit behaves like a clamped harmonic oscillator. Comparing it with a physical spring-mass damped oscillator having damping constant ′b′,'{b}^{'}, the correct equivalence would be:A LCR circuit behaves like a clamped harmonic oscillator. Comparing it with a physical spring-mass damped oscillator

Options

  1. AL↔m,C↔k,R↔bL ↔ m, C ↔ k, R ↔ b
  2. BL↔1b,C↔1m,R↔1kL ↔ \dfrac{1}{b}, C ↔ \dfrac{1}{m}, R ↔ \dfrac{1}{k}
  3. CL↔k,C↔b,R↔mL ↔ k, C ↔ b, R ↔ m
  4. DL↔m,C↔1k,R↔bL ↔ m, C ↔ \dfrac{1}{k}, R ↔ b

Correct answer

D. L↔m,C↔1k,R↔bL ↔ m, C ↔ \dfrac{1}{k}, R ↔ b

Step-by-step solution

In damped oscillation ma+bv+kx=0ma + bv + kx = 0
A LCR circuit behaves like a clamped harmonic oscillator. Comparing it with a physical spring-mass damped oscillator
md2xdt2+bdxdt+kx=0…..(i)m\dfrac{{d}^{2}x}{d{t}^{2}} + b\dfrac{dx}{dt} + kx = 0 \ldots . . \left(i\right)
In the circuit
−iR−Ldidt−qc=0- iR - L\dfrac{di}{dt} - \dfrac{q}{c} = 0
Ld2qdt2+Rdqdt+1c.q=0..(ii)L\dfrac{{d}^{2}q}{d{t}^{2}} + R\dfrac{dq}{dt} + \dfrac{1}{c} . q = 0 . . \left(ii\right)
Comparing equation (i) and (ii)
m=L,b=R,k=1cm = L, b = R, k = \dfrac{1}{c}
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