NTA Abhyas JEE Main2020PhysicsAlternating CurrentPractice
The natural frequency of an L - C circuit is 125000 cycles / s . When a dielectric medium of dielectric constant K is introduced between the plates of the capacitor, the frequency decreases by 25 kHz . The value of K is
Options
- A3 . 05
- B2 . 18
- C1 . 56
- D1 . 74
Correct answer
C. 1 . 56
Step-by-step solution
f = 1 2 π L C When a dielectric is introduced the capacitance becomes C ⁡ ′ = K ⁡ C ⁡ ⇒ f ⁡ ' f = C ⁡ C ⁡ ' 125000 - 25000 125000 = C ⁡ KC 100 125 = 1 K K = 125 100 2 = 1.56