JEE Main20198 Apr 2019Evening ShiftPhysicsAlternating CurrentActual
A circuit connected to an ac source of emf e = e 0 sin ⁡ 100 t with t in seconds, gives a phase difference of π 4 between the emf e and current i . Which of the following circuits will exhibit this?
Options
- AR C circuit with R = 1 k Ω and C = 1 μ F
- BR L circuit with R = 1 k Ω and L = 1 m H
- CR L circuit with R = 1 k Ω and L = 10 m H
- DR C circuit with R = 1 k Ω and C = 10 μ F
Correct answer
D. R C circuit with R = 1 k Ω and C = 10 μ F
Step-by-step solution
ω = 100 rad/sec phase difference between e and i is given by tan θ = X R                       ∴ θ = π 4 so tan θ = tan π 4 = 1 in case of R L circuit X = X L = ω L And in case of R C circuit X = X c = 1 ω c For option A : R = 1000   Ω and X C = 1 ω C = 1 100 1 × 10 - 6 = 10000   Ω tan ⁡ θ = X C R ≠ 1 For option B : R = 10 3   Ω and X L = L ω = 10 - 3 100