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JEE Main 201816 AprilOnline

Exam: JEE Main
Year: 2018
Date: 16 April
Mode: Online
Subject: Physics
Chapter: Alternating Current

JEE Main 2018 · 16 April · Online · Physics · Alternating Current

A power transmission line feeds input power at 2300V to a step-down...

A power transmission line feeds input power at

2300V

to a step-down transformer with its primary windings having

4000

turns giving the output power at

230V

. If the current in the primary coil of the transformer is

5A

and its efficiency is

90%

, the output current would be:

Options

A $45A$
B $50A$
C $20A$
D $25A$

Correct answer

A. $45A$

Step-by-step solution

Efficiency,

η = 0.9 = \dfrac{{P}_{s}}{{P}_{p}}

{V}_{s}{I}_{s} = 0.9 \times {V}_{p}{I}_{p}

{I}_{s} = \dfrac{0.9 \times 2300 \times 5}{230} = 45A

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