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JEE Main 2007
Exam
JEE Main
Year
2007
Subject
Physics
Chapter
Alternating Current

JEE Main 2007 · Physics · Alternating Current

In an a.c. circuit the voltage applied is E=E_0 ω t . The resulting...

In an a.c. circuit the voltage applied is E=E0sin⁡ωt\mathrm{E}=\mathrm{E}_0 \sin \omega \mathrm{t}. The resulting current in the circuit is I=\mathrm{I}=\mathrm{I}0sin⁡(ωt−π2)_0 \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right). The power consumption in the circuit is given by

Options

  1. A\mathrm{P}=\frac{\mathrm{E}_0\mathrm{I}_0}{\sqrt{2}}
  2. BP=\mathrm{P}= zero
  3. C\mathrm{P}=\frac{\mathrm{E}_0\mathrm{I}_0}{2}
  4. DP2E0\mathrm{P} \sqrt{2} \mathrm{E}_0\mathrm{I}0_0

Correct answer

B. P=\mathrm{P}= zero

Step-by-step solution

cos⁡ϕ=0\cos \phi=0 So power =0=0
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