The energy of an electron in an orbit of the Bohr's atom is -0.04 E₀ eV where E₀ is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then 2 L h is _ _ _ _ :

Step-by-step solution

In Bohr's atom, the energy levels are E_n = - E₀ n^2 where E₀ is the ground state energy. Given E = -0.04E₀ , we have - E₀ n^2 = -0.04E₀ , which gives n^2 = 25 , so n = 5 . The angular momentum in Bohr's model is L = n = n h 2 . Therefore, 2 L h = 2 h n h 2 = n = 5 .