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JEE Main20257 Apr 2025Morning ShiftPhysicsAtomic PhysicsActual

For a hydrogen atom, the ratio of the largest wavelength of Lyman series to that of the Balmer series is.

Options

  1. A5: 36
  2. B5: 27
  3. C3: 4
  4. D27: 5

Correct answer

B. 5: 27

Step-by-step solution

Lyman 1 ₁ = R [ 1 1 - 1 4 ]= 3 R 4 ₁= 4 3 R ________...(1) and Balmer 1 ₂ = R [ 1 4 - 1 9 ]= 5 R 36 ₂= 36 5 R Then, ₁ ₂ = 5 27

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