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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2025 · 7 April · Morning Shift · Physics · Atomic Physics

In a hydrogen like ion, the energy difference between the 2^ nd...

In a hydrogen like ion, the energy difference between the 2nd 2^{\text{nd }} excitation energy state and ground is 108.8 eV. The atomic number of the ion is

Options

  1. A4
  2. B2
  3. C1
  4. D3

Correct answer

D. 3

Step-by-step solution

ΔE=13.6z2[1n12−1n22]\Delta \mathrm{E}=13.6 \mathrm{z}^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right]
(13.6)z2[11−19]=108.8(13.6) \mathrm{z}^2\left[\frac{1}{1}-\frac{1}{9}\right]=108.8
(13.6)(8)9(z2)=108.8\frac{(13.6)(8)}{9}\left(z^2\right)=108.8
z=3\mathrm{z}=3
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