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In Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at 10.2 V. The wavelength of light emitted by hydrogen atom when excited to the first excitation level is _________ nm . (Given hc =1245 eV nm , e =1.6 10⁻¹⁹ C ).

Correct answer

0

Step-by-step solution

aligned & 10.2 eV = hc & = 1245 eV - nm 10.2 eV =122.06 ~nm aligned

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