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The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is :

Options

  1. A4: 1
  2. B1: 4
  3. C2: 1
  4. D1: 2

Correct answer

A. 4: 1

Step-by-step solution

aligned & 1 = Rz ^2 ( 1 n ₁^2 - 1 n ₂^2 ) & 1 _ L = Rz ^2 ( 1 1^2 ) 1 _ B = Rz ^2 ( 1 2^2 ) & _ B _ L =4: 1 aligned

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