Exam

JEE Main

Year

2024

Date

6 April

Shift

Morning Shift

Subject

Physics

Chapter

Atomic Physics

JEE Main 2024 · 6 April · Morning Shift · Physics · Atomic Physics

The ratio of the shortest wavelength of Balmer series to the...

The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is :

Step-by-step solution

$$\begin{aligned} & \frac{1}{\lambda}=\mathrm{Rz}^2\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right) \\ & \frac{\frac{1}{\lambda_{\mathrm{L}}}=\mathrm{Rz}^2\left(\frac{1}{1^2}\right)}{\frac{1}{\lambda_{\mathrm{B}}}=\mathrm{Rz}^2\left(\frac{1}{2^2}\right)} \\ & \frac{\lambda_{\mathrm{B}}}{\lambda_{\mathrm{L}}}=4: 1\end{aligned}$$