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JEE Main 20246 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
6 April
Shift
Morning Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2024 · 6 April · Morning Shift · Physics · Atomic Physics

Radius of a certain orbit of hydrogen atom is 8.48 Ã… . If energy...

Radius of a certain orbit of hydrogen atom is 8.48A~…8.48 Ã…. If energy of electron in this orbit is E/xE / x. then x=x= _____ (Given a0=0.529A~…,E=\mathrm{a}_0=0.529 Ã…, E= energy of electron in ground state).

Correct answer

0

Step-by-step solution

We know r=0.529n2Z⇒8.48=0.529n21n2=16⇒n=4\begin{aligned} & \mathrm{r}=0.529 \frac{\mathrm{n}^2}{\mathrm{Z}} \Rightarrow 8.48=0.529 \frac{\mathrm{n}^2}{1} \\ & \mathrm{n}^2=16 \Rightarrow \mathrm{n}=4 \end{aligned}We know E∝1n2\mathrm{E} \propto \frac{1}{\mathrm{n}^2}Enth =E16x=16\begin{aligned} & E_{n^{\text{th }}}=\frac{E}{16} \\ & x=16 \end{aligned}$$
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