The mass defect in a particular reaction is 0 . 4g . The amount of...

Energy liberated is given by, $E = ∆ m{c}^{2}$

$= \left(0 . 4 \times {10}^{- 3}\right) \times {\left(3 \times {10}^{8}\right)}^{2}$

$= 3600 \times {10}^{7}kWs$

$= \dfrac{3600 \times {10}^{7}}{3600}kWh = 1 \times {10}^{7}kWh$