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The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly :

Options

  1. A1 . 5 eV
  2. B13 . 6 eV
  3. C1 . 9 eV
  4. D12 . 1 eV

Correct answer

D. 12 . 1 eV

Step-by-step solution

For Balmer series, transition is from n = 3 , 4 , 5 , 6 , e t c to n = 2 . For transition to n = 2 , the minimum state to transition from is n = 3 . Therefore, energy required Δ E = E 3 - E 1 = - 13 . 6 9 - - 13 . 6 = 12 .1 eV

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