The wavelength of the radiation emitted is λ 0 when an electron jumps from the second excited state to the first excited state of hydrogen atom. If the electron jumps from the third excited state to the second orbit of the hydrogen atom, the wavelength of the radiation emitted will be 20 x λ 0 . The value of x is________.

Step-by-step solution

_ _ _ _ _   n = 4 _ _ _ _ _   n = 3 _ _ _ _ _   n = 2 _ _ _ _ _   n = 1 The wavelength of the light released when an electron jumps from higher energy state n 2 to lower energy state n 1 is 1 λ = R 1 n 1 2 - 1 n 2 2 , here, λ is wavelength, R is Rydberg Constant. When transition is from second excited state to first excited state, n = 3 → n = 2 1 λ 0 = R 1 2 2 - 1 3 2         . . . 1 When transition is from third excited state to second orbit n = 4 &#8594