A photon is emitted in transition from n = 4 to n = 1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h = 4 × 10 - 15 eV s )

Step-by-step solution

Using the relation between energy of photon and wavelength for the transition in the hydrogen atom, we get h c λ = 13 . 6 1 n 1 2 - 1 n 2 2 ⇒ 4 × 10 - 15 × 3 × 10 8 λ = 13 . 6 1 - 1 16 ⇒ λ = 12 × 10 - 7 × 16 13 . 6 × 15 = 94 . 1 × 10 - 9 = 94 . 1   nm