In Bohr's atomic model of hydrogen, let K, P and E are the kinetic...

Total energy of electron is stated as $E = - \dfrac{{Z}^{2}m{e}^{4}}{8{\left(nh{ε}_{0}\right)}^{2}}$, potential energy $P = - \dfrac{{Z}^{2}m{e}^{4}}{4{\left(nh{ε}_{0}\right)}^{2}}$ and kinetic energy is given by $K = \dfrac{{Z}^{2}m{e}^{4}}{8{\left(nh{ε}_{0}\right)}^{2}}$.

So, as electron makes transition to higher level, total energy and potential energy increases due to the negative sign while the kinetic energy of electron decreases.