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JEE Main 201815 AprilMorning ShiftOnline
Exam
JEE Main
Year
2018
Date
15 April
Shift
Morning Shift
Mode
Online
Subject
Physics
Chapter
Atomic Physics

JEE Main 2018 · 15 April · Morning Shift · Online · Physics · Atomic Physics

The energy required to remove the electron from a singly ionized...

The energy required to remove the electron from a singly ionized Helium atom is 2.22.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is:

Options

  1. A20eV20 \mathrm{eV}
  2. B79eV79 \mathrm{eV}
  3. C109eV109 \mathrm{eV}
  4. D34eV34 \mathrm{eV}

Correct answer

B. 79eV79 \mathrm{eV}

Step-by-step solution

Energy required to remove e−\mathrm{e}^{-}from singly ionized helium atom =(13.6)Z212=54.4eV=\frac{(13.6) Z^2}{1^2}=54.4 \mathrm{eV} (∵Z=2)(\because \mathrm{Z}=2) Energy required to remove e−\mathrm{e}^{-}from helium atom =xeV=x \mathrm{eV} According to question, 54.4eV=2.2x⇒x54.4 \mathrm{eV}=2.2 \mathrm{x} \Rightarrow \mathrm{x} =24.73eV=24.73 \mathrm{eV} Therefore, energy required to ionize helium atom =(54.4+24.73)eV=79.12eV=(54.4+24.73) \mathrm{eV}=79.12 \mathrm{eV}
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